Test Writing: Binary Tree Count Equal to Child

Created By: Geoffrey Challen

/ Version: 2020.11.0

Create a method named countEqualToEitherChild that accepts a single BinaryTree<*>? and counts the number of nodes in the tree where the value at that node is equal to either the value at its right child or the value at its left child. Keep in mind that not every node has a right or left child, so you'll need to check for null carefully. (Or use try-catch!) However, you can assume that all of the values in the tree are non-null.

For reference, cs125.trees.BinaryTree is defined like this:

Test Design Challenge

You're challenge is to write tests for this problem described above.

• Provide a public class named TestBinaryTreeCounter with a single non-private class method named test that accepts no arguments and does not return a value.
• If the implementation of the class described above is incorrect, your test method should throw an exception.
• If it is correct, do not throw an exception.
• You may want to use Kotlin's assert or check methods